Discover why checking if 1000000000000000 exists within a range up to 1000000000000001 is surprisingly fast in Python 3 and how Python's design enables such efficiency.
You might be surprised to learn that the Python 3 code 1000000000000000 in range(1000000000000001) runs incredibly fast, especially if you're used to the behavior of range in Python 2. The reason for this speed difference highlights a key optimization introduced in Python 3's range function.
The reason why the code 1000000000000000 in range(1000000000000001) is surprisingly fast in Python 3 boils down to how the range function works in Python 3 compared to Python 2.
In Python 2, range(n) would actually create a list of all the numbers from 0 to n-1. This means that range(1000000000000001) would attempt to create a list with a trillion elements, consuming a massive amount of memory and time.
However, Python 3 introduced a significant optimization. The range function in Python 3 doesn't create a list of all the numbers at once. Instead, it generates the numbers one by one as you need them. This is similar to how generators work in Python.
This "lazy evaluation" means that when you use 1000000000000000 in range(1000000000000001), Python doesn't actually calculate all the numbers from 0 to 1000000000000000. Instead, it only needs to check if 1000000000000000 exists within the bounds defined by the range object (which is very fast).
Therefore, the code executes quickly because it avoids generating a massive list and only performs a simple boundary check.
This Python code demonstrates the memory efficiency of Python 3's range object. It creates a range object representing a vast sequence of numbers and shows that its memory size remains small. It then efficiently checks if a large number exists within the range without calculating all the numbers. The commented-out code highlights the potential memory issues of creating a list with all the numbers in the range. This emphasizes the lazy evaluation benefit of Python 3's range, making it faster and more memory-friendly for large ranges.
import sys
# Python 3 range - Lazy Evaluation
range_obj = range(1000000000000001)
print(f"Size of range object: {sys.getsizeof(range_obj)} bytes")
if 1000000000000000 in range_obj:
print("Found the number!")
# For comparison, let's try creating a list in Python 3
# (Don't run this, it will likely crash your machine!)
# large_list = list(range(1000000000000001)) Explanation:
range(1000000000000001): This line creates a range object in Python 3. Importantly, it doesn't calculate all the numbers within the range yet.sys.getsizeof(range_obj): This line demonstrates that the range object itself has a very small memory footprint, regardless of the range it represents.1000000000000000 in range_obj: This is where the magic happens. Python 3's range object only needs to check if the specified number (1000000000000000) falls within its start and stop values. This is a very fast operation.Key Takeaway:
The speed improvement in Python 3's range function comes from its lazy evaluation approach. It avoids unnecessary calculations and memory allocation, making it significantly faster and more efficient, especially for large ranges.
xrange: While not mentioned in the article, Python 2 did have a memory-efficient alternative to range called xrange. It worked similarly to Python 3's range, generating numbers on demand. However, xrange was removed in Python 3, with range adopting its behavior.range is that it's an iterable but not a sequence. Iterables produce values one at a time, while sequences store all their elements in memory. This distinction is crucial for understanding the memory efficiency.range only works with them. For floating-point numbers or other data types, you'd need alternative techniques like generators or libraries like numpy.range object in a loop can still be time-consuming, even if it's memory-efficient.__contains__ Method: The speed of the in operator with range is due to the efficient implementation of the __contains__ special method. This method allows for quick checks within the defined range bounds.| Feature | Python 2 range()
|
Python 3 range()
|
|---|---|---|
| Implementation | Creates a list of all numbers in the range. | Creates an iterable object that generates numbers on demand. |
| Memory Usage | High: Stores the entire list in memory. | Low: Only stores the start, stop, and step values. |
| Speed | Slow for large ranges due to list creation. | Fast even for large ranges due to lazy evaluation. |
Explanation:
The code 1000000000000000 in range(1000000000000001) is surprisingly fast in Python 3 because of how the range function is implemented.
range() creates a full list, consuming significant memory and time for large ranges.range() creates an iterable object that generates numbers only when needed. This "lazy evaluation" avoids creating a massive list and performs a quick boundary check instead, making it much faster.In conclusion, the seemingly counterintuitive speed of 1000000000000000 in range(1000000000000001) in Python 3 is a testament to the optimization of the range function. By adopting lazy evaluation, Python 3's range avoids the memory and time overhead of creating large lists, making it significantly faster and more efficient for operations involving large number sequences. This optimization is a prime example of how Python 3 improves upon its predecessors, making it more suitable for a wider range of tasks, particularly those involving large datasets and complex computations.
Why "1000000000000000 in range(1000000000000001)" is so fast ... | Posted by u/stymiee - 295 votes and 22 comments
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Why is "1000000000000000 in range(1000000000000001)" so fast ... | A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions.> Why is "1000000000000000 in range(1000000000000001)" so fast in Python…
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